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Overview
Note that the extension of the Fisher exact test to r-by-c tables proposed by Fisher is also called the Fisher-Freeman-Halton test. For Fisher's exact test for r-by-c tables, SPSS requires installation of the Exact Tests add-on module. This, however, is rarely used. Rather, r-by-c tables are normally tested for significance using the chi-square test, possibly incorporating Yates' correction. Applied to the same 2-by-2 small sample data, uncorrected chi-square tends to underestimate the probability of observed cell counts, increasing Type I errors (false positive findings). Corrected chi-square will normally lead to the same significance decision as the Fisher exact test (see Sheskin, 2007: 637).
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| a | b | r1 |
| c | d | r2 |
| c1 | c2 | n |
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pobserved = 9!11!12!8!/20!7!2!5!6! = .132
pstronger = 9!11!12!8!/20!8!1!4!7! = .024
pstrongest = 9!11!12!8!/20!9!0!3!8! = .001
ptotal (one-tailed) = .157
(Recall factorial, denoted by !, is the arithmetic operation of multiplying 1 times 2 times 3, etc., up to n, for the case of n!)
In the example above, the next stronger and strongest tables have a combined probability of .025. The observed table has a probability of .132. When we add in this observed probability we get .157, which, being more than the .05 significance cutoff, leads us to conclude the relationship in the table is not significant. However, Tocher wishes to call attention to the fact that part or the .132 probability is below the .05 level (.05 - .025 = .025 is below), and part is above (.132 - .05 = .082 is above). Is the relationship in our particular sample assumed to be in the part above or below the cutoff level? Tocher's modification of the Fisher exact test is to use a random number process proportionate to the parts above and below the cutoff to determine whether or not to add the probability of pobserved as part of ptotal. If this process leads us to add it, as Fisher's exact test already does, then we conclude the relationship is not significant. However, if the process leads us not to add it, then the resulting ptotal is only .025, well below the .05 cutoff, and we consider that the relationship is significant.
How does Tocher's random number process work? In this example, the proportion of the probability of the observed table that is within (under) the .05 cutoff is .025/.132 = .189. Consulting a pseudo random number generator, as in SPSS, we get a random number in the range 0 to 1. If it is .189 or less, we do not add the observed probability to the total, otherwise we do.
Copyright 1998, 2008 by G. David Garson.
Last updated 4/23/08.